MATH SOLVE

2 months ago

Q:
# John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs to maintain a ratio of pumpkin to green beans of 3 to 1. If he wants to use a total of 64 cans, how many cans of green beans should he use?

Accepted Solution

A:

Answer:The number of Pumpkin can used = 48 cansThe number of Green Beans can used = 16 cansStep-by-step explanation:The ratio of Pumpkin to Green Beans = 3 : 1So, for every 3 can of Pumpkin, 1 can of green beans is used.Now, the total number of John wants to use = 64Let us assume the common factor in the ratio is m.⇒ The number of Pumpkin can used = 3 mThe number of Green Beans can used = 1 m = mSo, the Total cans used = Number of (Pumpkin + Green Beans) can ⇒ 3 m + m = 64or, 4 m = 64⇒ m = 64/ 4 = 16Hence, The number of Pumpkin can used = 3 m = 3 x 16 = 48 cansThe number of Green Beans can used = m = 16 cans