1.What are the coordinates of the circumcenter of this triangle?(__)2.DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . CF=8 cm and FG=6 cm.What is BG ?
Accepted Solution
A:
v(a) Let: a be the acceleration of the system, g be the acceleration due to gravity, T be the tension in the string.
For mA: T = mA a
For mB: mB g - T = mB a
Adding to eliminate T: mB g = (mA + mB)a ...(1)
a = mB g / (mA + mB) = 7.0 * 9.81 / (11.0 + 7.0) = 3.815 m/s^2 = 3.82 m/s^2 to 3 sig. fig.
(b) Let: s be the distance to the edge of the table, t be the time taken.
s = at^2 / 2 t = sqrt(2s / a) = sqrt(2 * 1.250 / 3.815) = 0.810 sec to 3 sig. fig.
(c) From (1): (mA + mB)(a / g) = mB mA(a / g) = mB(1 - a / g) mA = mB(g / a - 1) = 4.0(100 - 1) = 396 kg.